.:HSTuners::

*pdiggitydogg* · 12-08-2005, 01:50 PM

Can anyone check my work? I feel that its wrong...

ebpda9 · 12-08-2005, 02:38 PM

english please ? damn, it's been forever since i took a math course

*pdiggitydogg* · 12-08-2005, 02:50 PM

this is my last one!
Im trying to figure the area of the shaded protion (guess I forgot that...)
It just seems like my values are low.

(oh, and have you found that upper cover yet, stefan?)

MissJDM · 12-08-2005, 05:23 PM

Quote:

Originally posted by pdiggitydogg
this is my last one!
Im trying to figure the area of the shaded protion (guess I forgot that...)
It just seems like my values are low.

(oh, and have you found that upper cover yet, stefan?)

I would assume those numbers are given, but verify it for me before I go off trying to check it.

*pdiggitydogg* · 12-08-2005, 05:27 PM

only things given are the adjacent lengths (SqR(2), 1)...the angles are assumed to be correct...

x^2+y^2=4, so the hypotenuse of each = 2
Using pythagorean theorem, opposite sides (A,B) then equal SqR(2) SqR(3)

I think the formulas are correct....

MissJDM · 12-08-2005, 05:49 PM

Sigh, I feel like I'm letting you down..esp. 'cuz it's math! I haven't done trig/geo in awhile so I'm not too sure. I don't have a calc nearby so I don't know if they are correct but the method itself seems fine.

I'm having doubts on my answer.

Grip72 · 12-08-2005, 07:34 PM

SOB i forget math

i'm actually stoked to start up again

12-08-2005, 02:38 PM	#2
ebpda9 Repost Wagon Join Date: Dec 2001 Location: over here Age: 44 Posts: 17,266	english please ? damn, it's been forever since i took a math course __________________

12-08-2005, 05:49 PM	#6
MissJDM Registered User Join Date: Aug 2004 Location: West Coast Age: 38 Posts: 2,244	Sigh, I feel like I'm letting you down..esp. 'cuz it's math! I haven't done trig/geo in awhile so I'm not too sure. I don't have a calc nearby so I don't know if they are correct but the method itself seems fine. I'm having doubts on my answer. __________________ you say it best when you say nothing at all

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12-08-2005, 02:50 PM	#3
pdiggitydogg Yahoo Watashi wa kattaze! Join Date: May 2002 Location: Meanwhile, up in The D... Age: 41 Posts: 10,579	this is my last one! Im trying to figure the area of the shaded protion (guess I forgot that...) It just seems like my values are low. (oh, and have you found that upper cover yet, stefan?)

12-08-2005, 05:27 PM	#5
pdiggitydogg Yahoo Watashi wa kattaze! Join Date: May 2002 Location: Meanwhile, up in The D... Age: 41 Posts: 10,579	only things given are the adjacent lengths (SqR(2), 1)...the angles are assumed to be correct... x^2+y^2=4, so the hypotenuse of each = 2 Using pythagorean theorem, opposite sides (A,B) then equal SqR(2) SqR(3) I think the formulas are correct....

12-08-2005, 07:34 PM	#7
Grip72 Registered User Join Date: Apr 2002 Location: Calgary, AB Canada Age: 40 Posts: 2,962	SOB i forget math i'm actually stoked to start up again